================================================================ ================================================================ X-Sender: S9421793@mail.student.utwente.nl Mime-Version: 1.0 Date: Mon, 10 Jun 1996 12:36:23 +0100 To: KellySt@aol.com, kgstar@most.fw.hac.com, stevev@efn.org, jim@bogie2.bio.purdue.edu, zkulpa@zmit1.ippt.gov.pl, hous0042@maroon.tc.umn.edu, rddesign@wolfenet.com, David@InterWorld.com, lparker@destin.gulfnet.com, DotarSojat@aol.com, neill@foda.math.usu.edu, 101765.2200@compuserve.com, MLEN3097@Mercury.GC.PeachNet.EDU From: T.L.G.vanderLinden@student.utwente.nl (Timothy van der Linden) Subject: Re: Energy:momentum ratio To Steve: Words as "efficiency" and "convert" are only used to not make sentences more elaborate than they could be, I had not thought the word "efficiency" would create that much trouble, since one only needs an unit-conversion to make things right. It is this same origin that makes the word "convert" not 100% at its place. Even now, I can't find a single word would be satisfying, the only solution would be to use sentences like your: When you take something that has momentum, and you get energy out of it by slowing it down, you are getting the extra energy it has to compensate for its momentum (m^2 = E^2 - p^2). If m is constant, then when p increases E also increases. Even then, the words "get energy out of momentum" sounds much like "convert", "transfer" or "transform" which don't sound very well either. The derivation is as follows: The momentum of a particle with velocity v : p=gamma m v The energy of a particle with velocity v : E=m c^2 (gamma-1) p/E = v gamma / (c^2 (gamma-1)) Simplifying the above gives: p/E = 1/c {v/(c-Sqrt[c^2-v^2])} All units are according to S.I. (When mentioning energy, I only mean kinetic energy) TimothyDate: Mon, 10 Jun 1996 07:19:21 -0700 From: Genny Houston Mime-Version: 1.0 To: kellyst@aol.com Cc: kgstar@most.fw.hac.com Subject: [Fwd: Re: Energy:momentum ratio] Wow, Short, to the point, and full of math. I think Tim's a little peeved. ;) BTW, I wrote Dave and asked what his intentions are for LIT, I told him that I already got myself a domain name, and could not justify a virtual server at this time unless I thought that LIT was going to need space (no pun intended) I expect to hear back from him today or tommorrow. I really would like a big hit site like LIT to help generate ad money. I'd have to ask for about $20.00 from each of the members (as a donation only) to help with the startup costs, but then I would not everr ask for money again unless I absolutely had to. As long as URLy-bird makes money (I don't see how it can't) LIT will always have a home. Kevin Timothy van der Linden wrote: >To Steve: >Words as "efficiency" and "convert" are only used to not make sentences more elaborate than they could be, I had not thought the word "efficiency" would >The momentum of a particle with velocity v : p=gamma m v The energy of a particle with velocity v : E=m c^2 (gamma-1) >p/E = v gamma / (c^2 (gamma-1)) >Simplifying the above gives: >p/E = 1/c {v/(c-Sqrt[c^2-v^2])} >All units are according to S.I. >(When mentioning energy, I only mean kinetic energy) >Timothy ================================================================ ================================================================ X-Sender: kgstar@pophost.fw.hac.com Mime-Version: 1.0 Date: Mon, 10 Jun 1996 09:00:27 -0500 To: T.L.G.vanderLinden@student.utwente.nl (Timothy van der Linden) From: kgstar@most.fw.hac.com (Kelly Starks x7066 MS 10-39) Subject: Re: USING A ELECTROMAGNETIC BEAM TO PROPELL A STARSHIP Cc: KellySt@aol.com, kgstar@most.fw.hac.com, stevev@efn.org, jim@bogie2.bio.purdue.edu, zkulpa@zmit1.ippt.gov.pl, hous0042@maroon.tc.umn.edu, rddesign@wolfenet.com, David@InterWorld.com, lparker@destin.gulfnet.com, DotarSojat@aol.com, neill@foda.math.usu.edu, 101765.2200@compuserve.com, MLEN3097@Mercury.GC.PeachNet.EDU At 3:20 PM 6/8/96, Timothy van der Linden wrote: >>>>Of course if your using my hybrid fuel/sail configuration you want a havyer sail... ;) >>>Laser forth and maser back? >>Doesn't really matter. On the way out it depends on what lithium reflects best. On the way back probably the same thing, just so you don't need to build new beaming facilities. >>>>I worry about EM and secoundary reactions in the plasma. We are after all talking about hellish amounts of power. Even small percentages could incinerate the engine and ship. (Even a mile of Lithium might not protect the crew.) >>>OK, then we're back on one line... >>One line? >Eh, I guess my Dutch translation was a bit to litterally: >"We're in line with eachother" or "We're in agreement with each other" >Timothy Ah, like "in sync". Yeah, were together on the basic idea. Now how do you boost that much stuff!! Kelly ------------------------------------------------------------------ ---- Kelly Starks Internet: kgstar@most.fw.hac.com Sr. Systems Engineer Magnavox Electronic Systems Company (Magnavox URL: http://www.fw.hac.com/external.html) ------------------------------------------------------------------ ---- ================================================================ Date: Mon, 10 Jun 1996 08:58:49 -0700 From: Steve VanDevender To: T.L.G.vanderLinden@student.utwente.nl (Timothy van der Linden) Cc: KellySt@aol.com, kgstar@most.fw.hac.com, stevev@efn.org, jim@bogie2.bio.purdue.edu, zkulpa@zmit1.ippt.gov.pl, hous0042@maroon.tc.umn.edu, rddesign@wolfenet.com, David@InterWorld.com, lparker@destin.gulfnet.com, DotarSojat@aol.com, neill@foda.math.usu.edu, 101765.2200@compuserve.com, MLEN3097@Mercury.GC.PeachNet.EDU Subject: Re: Energy:momentum ratio Timothy van der Linden writes: >The derivation is as follows: >The momentum of a particle with velocity v : p=gamma m v The energy of a particle with velocity v : E=m c^2 (gamma-1) That's kinetic energy, not total energy. For many purposes kinetic energy is not particularly useful. Most importantly, when I say p/E is v, I use E to mean total energy (m*c^2*gamma in conventional units). >p/E = v gamma / (c^2 (gamma-1)) >Simplifying the above gives: >p/E = 1/c {v/(c-Sqrt[c^2-v^2])} >All units are according to S.I. >(When mentioning energy, I only mean kinetic energy) If you want to use kinetic energy as a quantity in your relativistic dynamics problems, be prepared for your analysis to get _a lot_ more complicated. I think I went into some detail in my original derivation about how I analyzed the relativistic dynamics of a ship reacting and ejecting a quantity of fuel. You might want to take a look at it again. The most unlikely result of your derivation is your claim that lower exhaust velocities are better. Does that mean that zero exhaust velocity is best, or is there instead an optimal velocity that is non-zero? >Timothy ================================================================ X-Sender: S9421793@mail.student.utwente.nl Mime-Version: 1.0 Date: Tue, 11 Jun 1996 00:06:42 +0100 To: KellySt@aol.com, kgstar@most.fw.hac.com, stevev@efn.org, jim@bogie2.bio.purdue.edu, zkulpa@zmit1.ippt.gov.pl, hous0042@maroon.tc.umn.edu, rddesign@wolfenet.com, David@InterWorld.com, lparker@destin.gulfnet.com, DotarSojat@aol.com, neill@foda.math.usu.edu, 101765.2200@compuserve.com, MLEN3097@Mercury.GC.PeachNet.EDU From: T.L.G.vanderLinden@student.utwente.nl (Timothy van der Linden) Subject: Re: Energy:momentum ratio To Steve, >If you want to use kinetic energy as a quantity in your relativistic dynamics problems, be prepared for your analysis to get _a lot_ more complicated. Yes, I assume you know that I and Rex independently have done such analysis's. We both have made documents that include some algebra that isn't always fun to look at. We also came to the conclusion that every fuel (combined with a Vend of the starship) has its own optimal Vexhaust. (More about this optimum in a few sentences) >The most unlikely result of your derivation is your claim that lower exhaust velocities are better. Does that mean that zero exhaust velocity is best, or is there instead an optimal velocity that is non-zero? I think you misunderstood the meaning of these formulas. In essence these formulas are just showing p/E ratios, they tell little about how they should be use, indeed for self-powered spaceships their use it limited (will come back on that in a minute), but for beaming stations on Earth they may be of direct use (that comes in another couple of minutes). To answer you question about the optimum, "Yes there is an optimum bigger than zero (and less than c)". Let me quote a few lines from my HTML-document: (Keep in mind that this assumes a certain constant Vend of the starship) The minimum exists because on the one hand, the higher Vexh the worse the energy/momentum ratio of the exhaust mass or because of the dumping of excess mass. And on the other hand, for low Vexh more mass is needed to get the same momentum, this means that unused fuel is used as propellant mass (this could easely be changed by increasing the fuel-factor). The complete document (large) should be here (with Dave): http://165.254.130.92/LIT/calc/calc.html To add some extra confusion ;) or to make things more complete I like to make clear why for beaming mass would be cheaper (in terms of energy) than beaming photons. For self-powered starships low exhaust velocities mean enormous amounts of propulsion mass to get the same total momentum. As one could imagine, part of that mass needs to move with the starship during the acceleration phase. This isn't handy because it makes everything harder to acclerate. But when one beames from Earth (or another source), it doesn't matter much how much mass is beamed, since one doesn't have the accelerate- the-mass-with you-problem (any other terminology?) that I described above for the starship. For constant momentum (the momentum that the starship needs for a specific Vend), and decreasing Vbeam the energy levels decrease: (Vbeam=v=the velocity of the beamed mass) E = p c {(c-Sqrt[c^2-v^2])/v} where {(c-Sqrt[c^2-v^2])/v} decreases for decreasing v Of course decreasing v means increasing M (gamma*m*v=fixed) but as long as the total energy decreases we don't care. (Mass is cheaper than energy isn't it?) OK, hope that your not confused by all the increases and decreases (and that I made no mistake in it). Now a more practical problem, the beam velocity cannot stay low at all times, since the starship accelerates and the beamed mass needs to catch up with the ship. Well actually this is not really a problem, only the p/E ratio gets worse, but it will always be better than when one uses photons. (It is only the same when mass moving with Vbeam=c) Timothy ================================================================ X-Sender: S9421793@mail.student.utwente.nl Mime-Version: 1.0 Date: Tue, 11 Jun 1996 00:06:50 +0100 To: KellySt@aol.com, kgstar@most.fw.hac.com, stevev@efn.org, jim@bogie2.bio.purdue.edu, zkulpa@zmit1.ippt.gov.pl, hous0042@maroon.tc.umn.edu, rddesign@wolfenet.com, David@InterWorld.com, lparker@destin.gulfnet.com, DotarSojat@aol.com, neill@foda.math.usu.edu, 101765.2200@compuserve.com, MLEN3097@Mercury.GC.PeachNet.EDU From: T.L.G.vanderLinden@student.utwente.nl (Timothy van der Linden) Subject: Re: USING A ELECTROMAGNETIC BEAM TO PROPELL A STARSHIP >Ah, like "in sync". Yeah, were together on the basic idea. Now how do you boost that much stuff!! Ah yes, "in sync" that is what I was looking for. About your question, we know the answers, all we need is the technology and the money :)) Tim ================================================================ From: David Levine To: "KellySt@aol.com" , "kgstar@most.fw.hac.com" , "stevev@efn.org" , "jim@bogie2.bio.purdue.edu" , "zkulpa@zmit1.ippt.gov.pl" , "hous0042@maroon.tc.umn.edu" To: "rddesign@wolfenet.com" , "lparker@destin.gulfnet.com" , "DotarSojat@aol.com" , "neill@foda.math.usu.edu" , "101765.2200@compuserve.com" <101765.2200@compuserve.com>, "MLEN3097@Mercury.GC.PeachNet.EDU" To: "'T.L.G.vanderLinden@student.utwente.nl'" Subject: RE: Energy:momentum ratio Date: Mon, 10 Jun 1996 18:20:55 -0400 Mime-Version: 1.0 >---------- >From: > T.L.G.vanderLinden@student.utwente.nl[SMTP:T.L.G.vanderLinden@student.utwen te.nl] >The complete document (large) should be here (with Dave): >http://165.254.130.92/LIT/calc/calc.html Hi, all. QUICK NOTE: Had some problems with the virtual server at 165.254.130.92, so try 165.254.130.90 instead. I think everything will work much better. URLs are still the same (http://165.254.130.90/LIT/calc/calc.html for example) For those of you FTPing documents, please use 165.254.130.90 now. Thanks. David (If anyone else wants an FTP account, let me know...)Date: Mon, 10 Jun 1996 21:26:59 -0700 ================================================================ X-Sender: kgstar@pophost.fw.hac.com Mime-Version: 1.0 Date: Tue, 11 Jun 1996 07:47:54 -0500 To: T.L.G.vanderLinden@student.utwente.nl (Timothy van der Linden) From: kgstar@most.fw.hac.com (Kelly Starks x7066 MS 10-39) Subject: Re: USING A ELECTROMAGNETIC BEAM TO PROPELL A STARSHIP Cc: KellySt@aol.com, kgstar@most.fw.hac.com, stevev@efn.org, jim@bogie2.bio.purdue.edu, zkulpa@zmit1.ippt.gov.pl, hous0042@maroon.tc.umn.edu, rddesign@wolfenet.com, David@InterWorld.com, lparker@destin.gulfnet.com, DotarSojat@aol.com, neill@foda.math.usu.edu, 101765.2200@compuserve.com, MLEN3097@Mercury.GC.PeachNet.EDU At 12:06 AM 6/11/96, Timothy van der Linden wrote: >>Ah, like "in sync". Yeah, were together on the basic idea. Now how do you boost that much stuff!! >Ah yes, "in sync" that is what I was looking for. >About your question, we know the answers, all we need is the technology and the money :)) >Tim All in all we've done fairly well. Most people still talk about starships as being impossible or talking centuries to get anywhere. We've at least figured out a technically plausible way to do it in a decade or two. Kelly ------------------------------------------------------------------ ---- Kelly Starks Internet: kgstar@most.fw.hac.com Sr. Systems Engineer Magnavox Electronic Systems Company (Magnavox URL: http://www.fw.hac.com/external.html) ------------------------------------------------------------------ ---- From: David Levine To: "KellySt@aol.com" , "hous0042@maroon.tc.umn.edu" , "T.L.G.vanderLinden@student.utwente.nl" , "stevev@efn.org" , "jim@bogie2.bio.purdue.edu" , "zkulpa@zmit1.ippt.gov.pl" To: "rddesign@wolfenet.com" , "lparker@destin.gulfnet.com" , "DotarSojat@aol.com" , "sl0c8@cc.usu.edu" , "MLEN3097@Mercury.GC.PeachNet.EDU" , "101765.2200@compuserve.com" <101765.2200@compuserve.com> To: "'kgstar@most.fw.hac.com'" Subject: RE: Opps Date: Wed, 12 Jun 1996 09:28:33 -0400 Mime-Version: 1.0 >Others. >The image map TOC's don't work. I will take a look at them. -David Date: Fri, 14 Jun 1996 00:56:36 -0400 From: KellySt@aol.com To: kgstar@most.fw.hac.com Subject: Fwd: Re: Sf movies & FX --------------------- ================================================================ X-Sender: S9421793@mail.student.utwente.nl Mime-Version: 1.0 Date: Sat, 15 Jun 1996 00:19:30 +0100 To: KellySt@aol.com, kgstar@most.fw.hac.com, stevev@efn.org, jim@bogie2.bio.purdue.edu, zkulpa@zmit1.ippt.gov.pl, hous0042@maroon.tc.umn.edu, rddesign@wolfenet.com, David@InterWorld.com, lparker@destin.gulfnet.com, DotarSojat@aol.com, neill@foda.math.usu.edu, 101765.2200@compuserve.com, MLEN3097@Mercury.GC.PeachNet.EDU From: T.L.G.vanderLinden@student.utwente.nl (Timothy van der Linden) Subject: Re: Post singularity society >>What about the third world? They think we're pretty freaky now. What if we start to radicaly change. Would they deside we were no longer human? >>Just a few thoughts. >>Kelly Yes, we touched this earlier, worrying if we could control them, me suggesting to create a virtual world to keep them in, so that they could never do us any harm, but us allowing to look inside to see how they "performed". One should consider what abilities one would like to have, speaking 20 languages fluently? Being able to compute the most difficult mathematical problems, figuring out the laws of the universe? Or how to love, to life in this world among and with others? I assume most of us are looking for a world that offers freedom (in all ways), eventually such a world will exist, the only problem then will be: What to choose... Another viewpoint is this: Today we are wondering, how should we treat nature, our origin and mother? In a few decades we need to take care of our children, they need upbringing, are we able to give them that? On the other hand, children can help to understand oneself better. Just some other thoughts... Timothy ================================================================= Date: Sat, 15 Jun 1996 14:04:34 -0400 From: KellySt@aol.com To: kgstar@most.fw.hac.com Subject: ox From: Shld Wulf Kelly St: Said: >I wonder how much space it takes to keep one in oxegen.< My figure is @ six liters of algea per person. That could be contained in a less than 2 meters of clear tubing, wrapp it helicaly around your light and go for it. ================================================================ X-Sender: S9421793@mail.student.utwente.nl Mime-Version: 1.0 Date: Sun, 16 Jun 1996 02:00:10 +0100 To: KellySt@aol.com, kgstar@most.fw.hac.com From: T.L.G.vanderLinden@student.utwente.nl (Timothy van der Linden) Subject: Hi Kelly, I've made time to read your HTML, About the "Space Settlement Designer's Corner", I know the numbers there aren't yours, but 15-20 kg of water as input seems very much. Also peeing over 7 liters of urine per day seems rather much. Could you explain what I'm overlooking, or am I just some one who use little water? In the "Externally Fueled Fusion Rocket" in the "Laser fuel launchers" paragraph you write: "If you space the tugs out every 60,000 miles for 100,000,000 kilometers..." The double metric standard is a bit confusing. A few lines further you write "... is 100,000 m/s^2, or about 100,000 G's." I assume you mean 10,000 G's (one zero less). You also say that such accelerations are acceptable, how sure are you about that? Finally you end with "The major problems with this system are the amount of reaction mass, and power, necessary to reach the desired maximum speeds may be prohibitive." You got me confused, what reaction mass are you talking about, all this was about lasers. I still don't see why one want to use a plasma shield instead of a solid one, could you repeat your latest arguements? A general note, a lot of your tables (not all) are cropped up (at least with the font I am using), for a reason not clear to me, you have added the WIDTH-tag in the tables, if you would just leave it out, the tables are automatically scaled. I suggest a table of contents at the top of several pages, especially the overview pages like "Mission flight type", "Future tech" and "Mission purpose", it gives an immediate overview of the page. I see you use "&;" instead of "& " in your "Support Ships: SSTO lander / Hypersonic Cruise Aircraft" page, try "& " the next time :) The "aero-lan.gif" image at this same page could be emphasized with the 'blue-border-link' so that people know they can get a better look by clicking on it. What I wonder about with these support ships, shouldn't they have a little bit more overcapacity, for example they should be able to do multiple landings and takeoffs at a more than 1g planet (at least 2 g). About the contents of all pages, it all seems OK, I wouldn't have expected otherwise, we have discussed everything several times. Timothy